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令x=被乘數, y=乘數=1~9, z=乘積的個位數=0~9,

則: x*y=88880+z => x=(88880+z)/y

有很多組解答,譬如: y=1, 有10組解

y=2, 有5組解, 詳細如下:

x=(88880+0)/2=44440

44440
*2
------
88880

x=(88880+2)/2=44441

44441
*2
------
88882

x=(88880+4)/2=44442

44442
*2
------
88884

x=(88880+6)/2=44443

44443
*2
------
88884

x=(88880+8)/2=44444

44444
*2
------
88888

y=3, z=1,4,7 => 有3組解

y=4, z=0,4,8 => 有3組解

y=5, z=0,5 => 有2組解

y=6, z=4 => 有1組解

y=7, z=6 => 有1組解

y=8, z=0,8 => 有2組解

y=9, z=4 => 有1組解

Sum=10+5+3+3+2+1+1+2+1=28組解

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