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請問解二次函數?求詳細過程
Aug 19th 2013, 13:29

原函數 y=-x^2+4x

向左平移3個單位，變為

y=-(x+3)^2+4(x+3)

=-x^2-2x+3

這樣做的想法很簡單，比如說(0,0)是函數中的一點

往左平移就變成了(-3,0)

所以要使得y=0，x就必須要+3回來

向下平移就更簡單了

(-3,0)往下移2單位，變成(-3,-2)

換句話說，y直接少掉了二

數學上的形式就是y=(-x^2-2x+3)-2=-x^2-2x+1

所以a=-2, b=1

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