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國小六年級數學問題

Oct 17th 2013, 17:37

那個解答應該是這樣解釋的;
4×67＝268
（268－196）
(將他們互減之後原本196隻裡頭原本屬於豬的腳被抵銷,但是鴨子的腳會被多減一遍,也就是說鴨子的腳被多減了72隻)÷（4－2）(然後除以鴨子的腳數目)＝36
67－36＝31
答：豬有　31　隻；鴨有　36　隻

轉換成x y的已經有人解答了,所以我就不說了

另外你說要用鴨去反推的話,過程是這樣
2*67=134
{134-196}(將他們互減之後原本196隻裡頭原本屬於鴨的腳被抵銷,但是豬的腳會被少減2隻腳,"是2隻腳"就是少減了半隻豬的意思)/{4-2}(所以你這邊應該要用半隻豬來做除數)=-31(但是物體沒有負的數目,所以是31隻豬)
答案;豬是31隻鴨是67-31=36

不過用鴨反推豬有點違反正常邏輯,因為正常情況物體的數量不是0就是大於0沒有那種是小於0的情況,總不會說這裡有負3個人吧(那已經是鬼了XD),而且豬正常來說也是4隻腳,這裡卻要使用只有2隻腳的豬會令人感到困惑.

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